105=7(1-2^n)/1-2

Solution for 105=7(1-2^n)/1-2 equation:

105=7(1-2^n)/1-2

We move all terms to the left:

105-(7(1-2^n)/1-2)=0

We multiply all the terms by the denominator


-(7(1-2^n)+105*1-2)=0


We calculate terms in parentheses: -(7(1-2^n)+105*1-2), so:

7(1-2^n)+105*1-2

determiningTheFunctionDomain
7(1-2^n)-2+105*1

We add all the numbers together, and all the variables

7(1-2^n)+103

We multiply parentheses

-14n+7+103

We add all the numbers together, and all the variables

-14n+110

Back to the equation:

-(-14n+110)


We get rid of parentheses

14n-110=0

We move all terms containing n to the left, all other terms to the right

14n=110

n=110/14

n=7+6/7